Tuesday, March 3, 2026

Operational Framework of Chemical Process Industries (CPI)

 

Operational Framework of Chemical Process Industries (CPI)

The primary objective of any chemical process industry is to convert raw material in valuable and useful final finished products. We cannot convert raw material directly into the final product, there area several intermediate steps which needs to be carried out to convert raw material into final finished product which is directly used in another industries or directly consumed by end user. Some of the steps may be easy and some of the processing steps are complex. Main processing steps involved in chemical process industry are shown in below diagram.

Figure 1: Processing Steps

 

Above diagram shows general steps and not applicable for all the chemical processing industries, it varies industry wise. Some industries may have additional processing steps and some steps may be omitted in some industries which is shown in above figure.

 

Step 1: Raw Material Storage: To produce any product, the basic requirement is raw material, without the raw material we cannot produce products. Sometimes it can be supplied to plant from the nearby plant if any plant is producing product which can be directly used as raw material for our production plant. It may be supplied to plant from plant which is located far from our plant and it may be transported by road or rail. Sometimes raw materials can be imported from other countries by ships (i.e. transportation LNG by large cargo ships). We should store enough raw material so that if we are not able to get raw material for some time than our production does not hamper. To store material, provision of storage tank or silos are to be provided in chemical process plant. Different types of storage tanks are installed to store liquid or gaseous raw material and for storage of solid material silos are provided. For unloading of raw material from tanker of ships to storage tanks, adequate unloading facilities are provided for smooth unloading operation.

Step 2: Feed Preparation: We cannot utilize these raw material into the process plant because it may contain some impurities which may damage process plant equipment, sometimes it acts as poison for the catalyst which is used in the reactor and deactivate the catalyst. Sometimes these impurities may react with other raw material and forms byproduct which is undesirable. So, it is necessary to separate out those impurities present in the raw material so it does not damage our process equipment. If our raw material is solid and size is differing form our process requirement so we need to install size reduction equipment (Crusher or Ball mill) to fulfil our process plant requirement. Sometimes we purchase raw material in liquid phase and store in the liquid phase (but we use raw material in vapour phase) so we need to install liquid vaporizer. For example, in nitric acid production plant, ammonia is used as a raw material and it is stored in liquid phase but it is used in the gas phase in the process. So, It is vaporised in vaporizer prior it enters to the ammonia oxidize(reactor).

Step 3: Reaction: This stage is the most crucial step for any chemical processing industry. To carry out reaction equipment used is known as reactor. Reactor is considered as heart of chemical process industries. In reactor raw material is converted into valuable raw products. Sometime along with main product some of the raw material which is fed to the reactor is converted into byproduct. Sometime more than one raw materials are mixed together and fed into the reactor. For example, in nitric acid production plant ammonia vapor is mixed air and then fed to the ammonia oxidizer (Tubular reactor).

Step 4: Product separation: As discussed in step 3, some side reactions are also happening in the reactor and it produce the undesirable byproducts. So, we need to separate these byproducts from our main products to meet consumer requirement. For that we need to use different types of separation techniques to purify our main product. For examples distillation, liquid-liquid extraction, Gas absorption, evaporation, adsorption, crystallization, drying are the methods used to purify our main product. For Example, in nitration on mono-chloro-benzene, we get four isomers of nitro-chloro-benzene (PNCB, MNCB, ONCB and DCNB). These four isomers are separated by the vacuum distillation followed by the crystallization. For separation of azeotropic mixture of water and hydrochloric acid, extractive distillation with concentrated sulfuric acid as entrainer. For concentration of fruit juice, evaporation is used.

Step 5: Purification: Sometime, the main product is converted into the desired purity product according to the customer’s requirement before sale because the requirement of the market is not the same, someone want the product with less purity and someone want product with high purity. For example, in sulfuric acid plant the concentration is sulfuric acid is decided based on the buyer. In petroleum refinery the quality of gasolene, diesel and kerosene depends on the end user.

Step 6: Product storage and logistics: After the above steps our final product is ready to sell in the market. It is not possible that all the product that we have produced in our plant is sold directly. Sometime the market demand is higher than the production capacity and sometime the market demand zero. We need to store the final finished product in somewhere in out plant. To store the final finished product, we need storage tank so we can supply the product to the market when the demand is high and we can store our product which is produced in our plant when the demand zero. In oil refineries and petrochemical plants separate plot area is provided and there are multiple tanks are installed to store raw material and products. After storage, the material is filled in drum or tankers for dispatch. If product is in solid form, then it will be packed in the plastic bags (jumbo bags) or box. In large chemical process plants, oil refineries and petrochemical complexes loading arm is used to load product in tanker from tank farm.  

A successful chemical process requires a balance between Unit Processes (chemical changes in the reactor) and Unit Operations (physical changes like separation and storage). As a professional in the field, understanding that "Product Separation" and "Purification" are often more energy-intensive than the reaction itself is key to optimizing plant efficiency.

                                                                                                                                   

Sunday, March 1, 2026

Centrifugal Pumps: Differential Head (∆H) Vs. Pressure (∆P)


Centrifugal Pumps: Differential Head (H) Vs. Pressure (P)

In the world of fluid mechanics, there is a common point of friction between Pump Manufacturers (who talk in "Head") and Plant Operators (who talk in "Pressure"). Understanding the distinction is vital for troubleshooting, pump selection, and equipment safety. 

A centrifugal pump is a constant head machine. This means that at a given RPM and flow rate, the pump will lift any liquid to the same height, regardless of its weight or density. 

Before going into discussion of differential head vs differential pressure in centrifugal pump we must know what does differential head (Total head) means for centrifugal pump.

We can specify differential head in various terminology.

Some of terminologies are:

·       Total work done on the fluid by the pump

·       Discharge vessel (Liquid level) elevation minus the suction vessel elevation (Liquid Level)

·       Discharge Head – Suction Head

·       Parameter which measures the pump’s ability to develop a specified discharge pressure

·       Discharge head plus the suction lift

·     Differential reading of pressure gauges which are installed on discharge side of the pump and the suction side of the pump

·       Parameter which measures the pump’s ability to raise the liquid to a specified height

Suction Head : It is the available head at the suction nozzle of the pump.

Discharge Head : It the vertical distance between the center line of the pump and the liquid level in the discharge vessel. Also referred as suction head plus the differential head developed by the pump.

Suction Lift : It is the difference between the pump center line elevation minus the suction vessel liquid level. It is applicable particularly when the liquid level in the suction vessel is below the center line of the pump. Also known as the negative suction head.

Figure 1: Differential Head

 

Differential head Vs Differential Pressure

             

Figure 2: Differential Head Vs Differential Pressure

 

Above figure 2 shows three identical pump which has the same differential which are used to pump three different liquids having specific gravity of X, Y and Z respectively.

Three pumps develop equal differential head irrespective of the fluid which is to be pumped. But the differential pressure developed by the pump varies with respect to change in the specific gravity of the fluid. Higher the specific gravity higher the differential pressure.

 

Figure 3: Differential Head Vs Differential Pressure

 

Above figure 3 shows three pumps (non identical) which develops the same differential pressure which are used to pump three different liquids having specific gravity of X, Y and Z respectively.

These three pumps develop same differential pressure. In this case these pumps develop different differential head. Differential head developed by the pump varies with respect to the specific gravity of the fluid which is to be pumped, Higher the specific gravity lower the differential head.

This concept of differential pressure and differential head creates confusion between the maintenance engineer who is working in the plant and the pump manufacturer. Maintenance people always read the pressure gauge reading and record when the pump manufacturer always use the word differential head for dictating the performance of the pump. A pump which is developing the head of 30 for water, the same pump will develop the same head for the concentrated sulfuric, gasoline or any other liquid irrespective of the liquid. Pump manufacturer doesn’t know the ultimate service of the pump when he is manufacturing pump. The pressure reading of the pressure gauges is function of the specific gravity. This the reason why we do not specify the pump by the differential pressure. If the maintenance engineer or the person wants to have a conversation with the manufacturer then, he must understand the concept of “Head”. This is the reason why the most of the pump sold without adequate gauges.

Formulas to convert differential head to differential pressure.

 

 

Example: A centrifugal pump which is capable of developing the differential head of 50 m (164 ft) at 10 m3/hr flowrate. Calculate differential pressure developed by the pump for the following mentioned fluids.

1.     Water having specific gravity of 1.0

2.     Benzene having specific gravity of 0.87

3.     Gasoline having specific gravity of 0.75

4.     Concentrated nitric acid having specific gravity of 1.5

5.     Concentrated sulfuric acid having specific gravity of 1.8

Answer: Differential pressure developed by the pump at 10 m3/hr flowrate is calculated below:

1.     Water having specific gravity of 1.0

·       Differential Pressure (psi) = Differential Head (ft) X Sp.gr. / 2.31

                                                                  = 164 X 1 / 2.31

                                                                  = 71 psi

·       Differential Pressure (kg/cm2) = Differential Head (m) X Sp.gr. / 10

                                                                          = 50 X 1 / 10

                                                                          = 5 kg/cm2

·       Differential Pressure (bar) = Differential Head (m) X Sp.gr. / 10.20

                                                                   = 50 X 1 / 10.20

                                                                   = 4.9 bar

 

2.     Benzene having specific gravity of 0.87

·       Differential Pressure (psi) = Differential Head (ft) X Sp.gr. / 2.31

                                                                  = 164 X 0.87 / 2.31

                                                                  = 61.8 psi

·       Differential Pressure (kg/cm2) = Differential Head (m) X Sp.gr. / 10

                                                                          = 50 X 0.87 / 10

                                                                          = 4.35 kg/cm2

·       Differential Pressure (bar) = Differential Head (m) X Sp.gr. / 10.20

                                                                   = 50 X 0.87 / 10.20

                                                                   = 4.3 bar

 

3.     Gasoline having specific gravity of 0.75

 ·       Differential Pressure (psi) = Differential Head (ft) X Sp.gr. / 2.31

                                                                     = 164 X 0.75 / 2.31

                                                                     = 53.24 psi

·       Differential Pressure (kg/cm2) = Differential Head (m) X Sp.gr. / 10

                                                                          = 50 X 0.75 / 10

                                                                          = 3.75 kg/cm2

·       Differential Pressure (bar) = Differential Head (m) X Sp.gr. / 10.20

                                                                   = 50 X 0.75 / 10.20

                                                                   = 3.67 bar

 

4.     Concentrated nitric acid having specific gravity of 1.5

·       Differential Pressure (psi) = Differential Head (ft) X Sp.gr. / 2.31

                                                                  = 164 X 1.5 / 2.31

                                                                  = 106.5 psi

·       Differential Pressure (kg/cm2) = Differential Head (m) X Sp.gr. / 10

                                                                          = 50 X 1.5 / 10

                                                                          = 7.5 kg/cm2

·       Differential Pressure (bar) = Differential Head (m) X Sp.gr. / 10.20

                                                                   = 50 X 1.5 / 10.20

                                                                   = 7.35 bar

 

5.     Concentrated sulfuric acid having specific gravity of 1.8

·       Differential Pressure (psi) = Differential Head (ft) X Sp.gr. / 2.31

                                                                  = 164 X 1.8 / 2.31

                                                                  = 127.8 psi

·       Differential Pressure (kg/cm2) = Differential Head (m) X Sp.gr. / 10

                                                                          = 50 X 1.8 / 10

                                                                          = 9 kg/cm2

·       Differential Pressure (bar) = Differential Head (m) X Sp.gr. / 10.20

                                                             = 50 X 1.8 / 10.20

                                                             = 8.8 bar


The Hidden Variable: Power Requirement

While the Head remains the same, the Brake Horsepower (BHP) required to move the fluid increases linearly with Specific Gravity.

 

 

Maintenance Tip: If you switch a pump from Water to Sulfuric Acid, the pressure gauge will go up, but so will the Amperage on the motor. Failure to account for the higher Sp.Gr can result in a tripped breaker or a burnt-out motor.

Conclusion

A pump manufacturer specifies "Head" because they do not know what fluid you will eventually pump. As a maintenance engineer, you must always convert your gauge readings (P) to Head (H) using the fluid's Specific Gravity before comparing your pump's performance against the manufacturer’s original test curve.